2k^2+5k-117=0

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Solution for 2k^2+5k-117=0 equation:



2k^2+5k-117=0
a = 2; b = 5; c = -117;
Δ = b2-4ac
Δ = 52-4·2·(-117)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-31}{2*2}=\frac{-36}{4} =-9 $
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+31}{2*2}=\frac{26}{4} =6+1/2 $

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